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Also, and form a linear pair. Therefore, On substituting in equation above, we get: In? This further simplifies to : Hence, the value of x is 20o.
Solution 29 : Jesus : The given rd sharma class 8 solutions chapter 9 Let us draw a line n parallel to l and m. Therefore, AMEN is a parallelogram. Since the angles are supplementary, therefore their sum must be equal to. We need to prove that It is given thattherefore, i Too, we havetherefore, ii From i and iiwe get: But these are the pair of corresponding angles. The questions provided in Rd Sharma Books are prepared in accordance with CBSE, thus holding higher chances of appearing on CBSE question papers. Or, we can say that: From the gusto above, and Therefore, It is given that: On comparing i and iiwe get: Putting in iwe get : Hence, the values for a and b areand respectively. Solution 17 : Answer : In the given problem, we have to find the value of i Con On cubing both sides we get, We shall use identity Hence the value of is ii Given On cubing both sides we get, We shall use identity Hence the value of is. Theorem states: If a transversal intersects two lines in such a way that a pair of consecutive interior custodes is supplementary, then the two lines are parallel. Adding this equation to iwe get: But these are the consecutive interior angles which are not supplementary. Also, and are the two angles on the same side of the transversal.
We know that is a right angle. Thus, From i and ii , we get: Hence, the correct choice is c.
Rd Sharma Class 9 Th Solutions - Hence our assumption is correct. On substituting these values in i , we get: It is given that: Therefore, Also, Therefore, Therefore, Solution 4 : Answer : Let us draw a straight line.
RD SHARMA CLASS 9 CH-4 SOLUTIONS CLASS 9 RD SHARMA CH-4 SOLUTIONS Home Class 9 Maths Maths : RD Sharma Class 9th Solutions RD Sharma Maths : Solutions for Class 9th Algebraic Identities Exercise 4. Solution 5 : Answer : In the given problem, we have to find Given On squaring both sides we get, We shall use the identity Hence the value of is. Solution 6 : Answer : In the given problem, we have to find and We have On squaring both sides we get, We shall use the identity Again squaring on both sides we get, We shall use the identity Hence the value ofis and is. Solution 7 : Answer : In the given problem, we have to find Given Adding and subtracting 2 on left hand side Hence the value of is Solution 8 : Answer : In the given problem, we have to find Given Adding and subtracting 2 on left hand side, Hence the value of is Solution 9 : Answer : In the given problem, we have to find We have been given and Let us take We shall use the identity By substituting and we get, Hence the value of is. Solution 10 : Answer : In the given problem, we have to find We have been given and Let us take On squaring both sides we get, We shall use the identity By substituting we get, Hence the value of is Solution 11 : Answer : In the given problem, we have to find We have been given and Let us take On squaring both sides we get, We shall use the identity By substituting we get, Hence the value of is. Solution 12 : Answer : i In the given problem, we have to find product of We have been given On rearranging we get, We shall use the identity By substituting,we get, We shall use the identity Hence the value of is ii In the given problem, we have to find product of We have been given On rearranging we get We shall use the identity By substituting,, we get , Hence the value of is iii In the given problem, we have to find product of On rearranging we get We shall use the identity By substituting , Hence the value of is iv In the given problem, we have to find product of On rearranging we get We shall use the identity Hence the value of is v In the given problem, we have to find product of Taking as common factor We shall use the identity Hence the value of is vi In the given problem, we have to find product of On rearranging we get We shall use the identity Hence the value of is. Solution 13 : Answer : In the given problem, we have to prove is always non negative for all that is we have to prove that Consider, Hence is always non negative for all Note: Square of all negative numbers is always positive or non negative. Solution 2 : Answer : In the given problem, we have to simplify the expressions i Given By using identity Hence the equation becomes Taking 2 as common factor we get Hence the simplified value of is ii Given By using identity Hence the equation becomes Taking 4 as common factor we get Hence the simplified value of is. Solution 3 : Answer : In the given problem, we have to find value of Given and Squaring the equation, we get Now putting the value of in above equation we get, Taking 2 as common factor we get Hence the value of is. Solution 4 : Answer : In the given problem, we have to find value of Given Multiply equation with 2 on both sides we get, Now adding both equation and we get We shall use the identity Hence the value of is. Solution 5 : Answer : In the given problem, we have to find value of Given Squaring both sides of we get, Substituting in above equation we get, Hence the value of is. Solution 6 : Answer : In the given problem, we have to find value of Given We have This equation can also be written as Using the identity Hence the value of is. Solution 7 : Answer : In the given problem, we have to simplify the value of each expression i Given We shall use the identity for each bracket By arranging the like terms we get Now adding or subtracting like terms, Hence the value of is ii Given We shall use the identity for expanding the brackets Now arranging liked terms we get, Hence the value of is iii Given We shall use the identity for each brackets Canceling the opposite term and simplifies Hence the value of is. Solution 2 : Answer : In the given problem, we have to simplify equation i Given We shall use the identity Here By applying identity we get Hence simplified form of expression is. Solution 3 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Hence the value of is. Solution 4 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Hence the value of is. Solution 5 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Hence the value of is Solution 6 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Hence the value of is Solution 7 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Hence the value of is. Solution 8 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, In order to find we are using identity Here and Hence the value of is. Solution 9 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, In order to find we are using identity Here and Hence the value of is. Solution 10 : Answer : In the given problem, we have to find the value of Given, In order to find we are using identity Here putting, Hence the value of is. Solution 11 : Answer : In the given problem, we have to find the value of Given, In order to find we are using identity Here putting,, Hence the value of is. Solution 13 : Answer : In the given problem, we have to find the value of numbers i Given In order to find we are using identity We can write as Hence where The value of is ii Given In order to find we are using identity We can write as Hence where The value of is iii Given In order to find we are using identity We can write as Hence where The value of is iv Given In order to find we are using identity We can write as Hence where The value of is v Given In order to find we are using identity We can write as Hence where The value of is vi Given In order to find we are using identity We can write as Hence where The value of is. Solution 14 : Answer : In the given problem, we have to find the value of numbers i Given We can write as We shall use the identity Here Hence the value of is ii Given We can write as We shall use the identity Here Hence the value of is iii Given We can write as We shall use the identity Here Hence the value of is iv Given We can write as We shall use the identity Here Hence the value of is. Solution 15 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Again squaring on both sides we get, We shall use the identity Again cubing on both sides we get, We shall use identity Hence the value of is respectively. Solution 16 : Answer : In the given problem, we have to find the value of Given By adding and subtracting in left hand side of we get, Again by adding and subtracting in left hand side of we get, Now cubing on both sides of we get we shall use identity Hence the value of is respectively. Solution 17 : Answer : In the given problem, we have to find the value of i Given On cubing both sides we get, We shall use identity Hence the value of is ii Given On cubing both sides we get, We shall use identity Hence the value of is. Solution 18 : Answer : From given problem we have to find the value of Given On cubing both sides of we get We shall use identity Hence the value of is. Solution 19 : Answer : In the given problem, we have to find the value of Given Cubing on both sides of we get We shall use identity Hence the value of is. Solution 2 : Answer : In the given problem, we have to find the value of equation using identity i Given We shall use the identity We can rearrange the as Now substituting the value in we get, Hence the Product value of is ii Given We shall use the identity We can rearrange the as Now substituting the value in we get, Hence the Product value of is iii Given We shall use the identity, We can rearrange the as Now substituting the value in Taking Least common multiple, we get Hence the Product value of is iv Given We shall use the identity We can rearrange the as Now substituting the value in we get, Taking Least common multiple, we get Hence the Product value of is v Given We shall use the identity, We can rearrange the as Now substituting the value in Taking Least common multiple, we get Hence the Product value of is. Solution 3 : Answer : In the given problem, we have to find the value of Given We shall use the identity We can rearrange the identity as Now substituting values in as, We can write as Now rearrange as Thus Now substituting values Hence the value of is respectively. Solution 3 : Answer : In the given problem, we have to find the value of Given We shall use the identity We can rearrange the identity as Now substituting values in as, We can write as Now rearrange as Thus Now substituting values Hence the value of is respectively. Solution 4 : Answer : In the given problem, we have to find the value of Given We shall use the identity Hence the value of is. Solution 5 : Answer : In the given problem, we have to find the value of Given We shall use the identity Hence the value of is. Solution 3 : Answer : In the given problem, we have to find value of Given We shall use the identity We know that Here substituting we get, Hence the value of is. Solution 4 : Answer : In the given problem, we have to find value of Given We shall use the identity We know that Here substituting we get Hence the value of is. Solution 2 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Hence the value of is Hence the correct choice is d. Solution 3 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here put, Squaring on both sides we get, Hence the value of is Hence the correct choice is b. Solution 4 : Answer : In the given problem, we have to find the value of Given We shall use the identityand Here put, Take Cube on both sides we get, Hence the value of is Hence the correct choice is d. Solution 5 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here put, We shall use the identitywe get, Taking square root on both sides we get, Hence the value of is Hence the correct choice is c. Solution 6 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Hence the value of is Hence the correct choice is b. Solution 9 : Answer : Given Using identity Here, Again using identity Here Substituting Using identity Here Hence the value of is The correct choice is b. Solution 10 : Answer : In the given problem, we have to find the value of Given We shall use the identity Here putting, Substitute in we get, Hence the value of is Hence the correct choice is b. Solution 11 : Answer : We have to find the value of Given Using identity we get, Here Substituting we get, By transposing left hand side we get, Again using identity we get, Substituting we get Using identity we get Here Substituting we get, The value of is The correct choice is b Solution 12 : Answer : Given Multiplying both sides by 2 we get, Therefore the sum of positive quantities is zero if and only if each quantity is zero. If, then The correct choice is d. Solution 13 : Answer : We have to find Given Using identity Hence the value of The correct choice is d. Solution 14 : Answer : Given Using identity we get Here Taking Cube on both sides we get, Hence the value of is The correct choice is. Solution 15 : Answer : We have to find Given Using identity we get, By transposing +46 to left hand side we get, Hence the value of is The correct choice is a. Solution 16 : Answer : We have to find the value of Given Using identity we get, By transposing +46 to left hand side we get, Using identity The value of is Hence the correct choice is. Solution 17 : Answer : Given Using identity Here Hence the Value of is The correct choice is. Solution 18 : Answer : We have to find the value of Using Identity we get, Hence the value of is The correct choice is. Solution 19 : Answer : We have to find the product of Using identity We can rearrange as Again using the identity Here Hence the product of is The correct choice is. Solution 20 : Answer : Given Taking Least common multiple in we get, Using identity Hence the value of is The correct choice is d. Solution 21 : Answer : We have to find the product of Using identity Here Hence the product value of is The correct alternate is. Solution 22 : Answer : To find the value of Given Using identity Here we get Transposing -288 to left hand side we get Hence the value of is -224 The correct choice is. Solution 23 : Answer : We have to find the possible dimension of cuboid Given: volume of cuboidcuboid Take 3 as common factor Using identity We get, Here the dimension of cuboid s' is 3, The correct alternate is. Solution 24 : Answer : Given Using identity we get, Hence the value of is. The correct choice is d. Solution 25 : Answer : We have to find the product of Using identity Here Hence the product of is 10,000 The correct choice is. Solution 26 : Answer : Given Using the identity Hence is equal to The correct choice is. Solution 2 : Answer : We have to find the value of Given Using identity Here By substituting the value of We get, By transposing + 2 to left hand side, we get Cubing on both sides we get, Using identity Here Put we get By transposing + 21 to left hand side we get , Hence the value of is. Solution 3 : Answer : We have to find the value of Given Using identity By substituting the value of we get By transposing +24 to left hand side we get , Hence the value of is.